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30m^2+72m-54=0
a = 30; b = 72; c = -54;
Δ = b2-4ac
Δ = 722-4·30·(-54)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-108}{2*30}=\frac{-180}{60} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+108}{2*30}=\frac{36}{60} =3/5 $
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